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Re: [hobbit] EXHOST regular expression syntax



Regular expression syntax Hobbit


###################################
#        +      Add
#        -      Subtract
#        *      Multiply
#        /      Divide
#        %      Modulo
#        |      Bit-wise "or"
#        &      Bit-wise "and"
#        ||     Logical "or"
#        &&     Logical "and"
#        >      Greater than
#        <      Less than
#        >=     Greater than or equal
#        <=     Less than or equal
#        ==     Equal
###################################


http://hobbitmon.sourceforge.net/docs/man5/bbcombotest.cfg.5.html

2008/4/22, Johann Eggers <Johann.Eggers (at) teleatlas.com>:
> > The rule that used to work is like this:
> > PROC	dsmc EXHOST=%.jotunn.rhi.hi.is
> >
> > Now, yet another host is also exempt from the rule, so
> > I tested the following rules:
> > PROC	dsmc EXHOST=%.jotunn.rhi.hi.is EXHOST=bestla.rhi.hi.is
> > PROC	dsmc EXHOST=%.jotunn.rhi.hi.is,bestla.rhi.hi.is
> >
> > Both rules give unexpected results. So I expect that the rule
> > should be written as a single regular expression, but I
> > do not know the syntax. Can anybody refer me to a description
> > of the syntax.
>
> Hi,
>
> Try using this:
>
> PROC dsmc EXHOST=%(jotunn.rhi.hi.is|bestla.rhi.hi.is)
>
> -Johann
>
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>
>


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