[hobbit] os count

[Root, Paul]

I wrote a script that does a similar thing. It connects to each machine
and does a uname. 
Being Solaris centric, I split it up by solaris version (and zone). 

I ran your script on my server, and it gives me 50 more machines than I
think I have. 
It certainly doesn't add up to the entries in the bb-hosts file. 

I print out a chart of each machine's level then sum it up like this:

Host Count:
    noconn : 29
      zone : 57
       5.7 : 2
       5.8 : 2
       5.9 : 11
      5.10 : 32
     nossh : 44
     Linux : 7
     TOTAL : 184


I haven't had time, but I need/want to graph this. 



Paul Root
Lead Internet Systems Eng
Network Services
 

-----Original Message-----
From: michael nemeth [mailto:michael.nemeth at lmco.com] 
Sent: Thursday, November 20, 2008 7:11 AM
To: hobbit at hswn.dk
Subject: [hobbit] os count

Did did a little perl program that does an os count produces count like
hp-ux   3
linux      1
sunos    38.

Run as a stand alone did not see the need to run out of hobbit.
But Henrik wouldn't this be easy enough to add in to bbtest?
Here it is:

#!/usr/local/bin/perl
eval 'exec /usr/local/bin/perl -S $0 ${1+"$@"}'
    if $running_under_some_shell;
                        # this emulates #! processing on NIH machines.
                        # (remove #! line above if indigestible)

eval '$'.$1.'$2;' while $ARGV[0] =~ /^([A-Za-z_0-9]+=)(.*)/ && shift;
                        # process any FOO=bar switches

$[ = 1;                 # set array base to 1
$BBHOME="/home/mnemeth/sunhobbit/";
open (HOB, "$BBHOME/server/bin/bb 127.0.0.1 'hobbitdboard fields=BBH_OS 
test=info' |") ;

while (<HOB>) {
    chomp;      # strip record separator
    @Fld = split(' ', $_, -1);

    for ($i = 1; $i <= $#Fld; $i++) {
        $freq{$Fld[$i]}++;
    }
}

foreach $word (sort keys %freq) {
    printf "%s\t%d\n", $word, $freq{$word};
}


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